0=-5.6t^2+108

Solution for 0=-5.6t^2+108 equation:

0=-5.6t^2+108

We move all terms to the left:

0-(-5.6t^2+108)=0

We add all the numbers together, and all the variables

-(-5.6t^2+108)=0

We get rid of parentheses

5.6t^2-108=0

a = 5.6; b = 0; c = -108;
Δ = b2-4ac
Δ = 02-4·5.6·(-108)
Δ = 2419.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{2419.2}}{2*5.6}=\frac{0-\sqrt{2419.2}}{11.2}
=-\frac{\sqrt{}}{11.2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{2419.2}}{2*5.6}=\frac{0+\sqrt{2419.2}}{11.2}
=\frac{\sqrt{}}{11.2}
$